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Note that it's possible to do this:
public <T> List<T> getList() {
return (List<T>)ts;
}
without the ghastly Class<T> param, and make use of one of the few cases
where Java can infer type params:
List<Foo> myList = listView.getList()
I write type-inferring factories all the time like this:
static <T> ArrayList<T> makeArrayList() {
return new ArrayList<T>();
}
List<Foo<Bar<List<Baz>>>> = makeArrayList();
To only specify types once.
Of course, this has the same problem of errors only showing up at
runtime, and in a depressingly high number of cases, you still need to
specify the <T> using Java's weird syntax - listView.<Foo>getList().
calathus wrote:
>
> On Tue, Jan 25, 2011 at 11:42 AM, Greg Brown <[email protected]
> <mailto:[email protected]>> wrote:
>
> > Since generic version may give wrong impression that it is type safe,
> it
> may be better to provide two version for getter, one is just return
> List<object>, another will return List<T> taking class value as the
> argument. also we may use generic method for setter. see following sample
> code.
> ...
> > public List<Object> getList() {
> > return (List<Object>)ts;
> > }
> > public <T> List<T> getList(Class<T> cls) {
> > return (List<T>)ts;
> > }
>
> Yuck. I think it is probably best to leave it as-is.
>
>
> I think this approach will eliminate using cast for adding element(which is
> very
> frequently used), while current one still requires cast.
> And I think most of case, the second case won't be required.
>
>
>
>
>
> --
> Cheers,
> calathus
>
>
>
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