I created https://issues.apache.org/jira/browse/SPARK-2620 to track this.
Maybe useful to know, this is a regression on Spark 1.0.0. I tested the
same sample code on 0.9.1 and it worked (we have several jobs using case
classes as key aggregators, so it better does)
-kr, Gerard.
On Tue, Jul 22, 2014 at 5:37 PM, Gerard Maas <gerard.m...@gmail.com> wrote:
> Yes, right. 'sc.parallelize(ps).map(x=> (**x.name**,1)).groupByKey().
> collect'
> An oversight from my side.
>
> Thanks!, Gerard.
>
>
> On Tue, Jul 22, 2014 at 5:24 PM, Daniel Siegmann <daniel.siegm...@velos.io
> > wrote:
>
>> I can confirm this bug. The behavior for groupByKey is the same as
>> reduceByKey - your example is actually grouping on just the name. Try
>> this:
>>
>> sc.parallelize(ps).map(x=> (x,1)).groupByKey().collect
>> res1: Array[(P, Iterable[Int])] = Array((P(bob),ArrayBuffer(1)),
>> (P(bob),ArrayBuffer(1)), (P(alice),ArrayBuffer(1)),
>> (P(charly),ArrayBuffer(1)))
>>
>>
>> On Tue, Jul 22, 2014 at 10:30 AM, Gerard Maas <gerard.m...@gmail.com>
>> wrote:
>>
>>> Just to narrow down the issue, it looks like the issue is in
>>> 'reduceByKey' and derivates like 'distinct'.
>>>
>>> groupByKey() seems to work
>>>
>>> sc.parallelize(ps).map(x=> (x.name,1)).groupByKey().collect
>>> res: Array[(String, Iterable[Int])] = Array((charly,ArrayBuffer(1)),
>>> (abe,ArrayBuffer(1)), (bob,ArrayBuffer(1, 1)))
>>>
>>>
>>>
>>> On Tue, Jul 22, 2014 at 4:20 PM, Gerard Maas <gerard.m...@gmail.com>
>>> wrote:
>>>
>>>> Using a case class as a key doesn't seem to work properly. [Spark 1.0.0]
>>>>
>>>> A minimal example:
>>>>
>>>> case class P(name:String)
>>>> val ps = Array(P("alice"), P("bob"), P("charly"), P("bob"))
>>>> sc.parallelize(ps).map(x=> (x,1)).reduceByKey((x,y) => x+y).collect
>>>> [Spark shell local mode] res : Array[(P, Int)] = Array((P(bob),1),
>>>> (P(bob),1), (P(abe),1), (P(charly),1))
>>>>
>>>> In contrast to the expected behavior, that should be equivalent to:
>>>> sc.parallelize(ps).map(x=> (x.name,1)).reduceByKey((x,y) =>
>>>> x+y).collect
>>>> Array[(String, Int)] = Array((charly,1), (abe,1), (bob,2))
>>>>
>>>> Any ideas why this doesn't work?
>>>>
>>>> -kr, Gerard.
>>>>
>>>
>>>
>>
>>
>> --
>> Daniel Siegmann, Software Developer
>> Velos
>> Accelerating Machine Learning
>>
>> 440 NINTH AVENUE, 11TH FLOOR, NEW YORK, NY 10001
>> E: daniel.siegm...@velos.io W: www.velos.io
>>
>
>
