Thanks Zongheng for the pointer. Is there a way to achieve the same in
1.0.0 ?
On Thu, Jul 31, 2014 at 1:43 PM, Zongheng Yang <zonghen...@gmail.com> wrote:
> countDistinct is recently added and is in 1.0.2. If you are using that
> or the master branch, you could try something like:
>
> r.select('keyword, countDistinct('userId)).groupBy('keyword)
>
> On Thu, Jul 31, 2014 at 12:27 PM, buntu <buntu...@gmail.com> wrote:
> > I'm looking to write a select statement to get a distinct count on userId
> > grouped by keyword column on a parquet file SchemaRDD equivalent of:
> > SELECT keyword, count(distinct(userId)) from table group by keyword
> >
> > How to write it using the chained select().groupBy() operations?
> >
> > Thanks!
> >
> >
> >
> > --
> > View this message in context:
> http://apache-spark-user-list.1001560.n3.nabble.com/SchemaRDD-select-expression-tp11069.html
> > Sent from the Apache Spark User List mailing list archive at Nabble.com.
>
