Hi Sameer,
MLLib uses Breezeās vector format under the hood. You can use that.
http://www.scalanlp.org/api/breeze/index.html#breeze.linalg.SparseVector
For example:
import breeze.linalg.{DenseVector => BDV, SparseVector => BSV, Vector => BV}
val numClasses = classes.distinct.count.toInt
val userWithClassesAsSparseVector = rows.map(x => (x.userID, new
BSV[Double](x.classIDs.sortWith(_ < _),
Seq.fill(x.classIDs.length)(1.0).toArray, numClasses).asInstanceOf[BV[Double]]))
Chris
On Sep 15, 2014, at 11:28 AM, Sameer Tilak <[email protected]> wrote:
> Hi All,
> I have transformed the data into following format: First column is user id,
> and then all the other columns are class ids. For a user only class ids that
> appear in this row have value 1 and others are 0. I need to crease a sparse
> vector from this. Does the API for creating a sparse vector that can directly
> support this format?
>
> User id Product class ids
>
> 2622572 145447 1620 13421 28565 285556 293 4553 67261
> 130 3646 1671 18806 183576 3286 51715 57671 57476