That's not quite what I'm looking for.  Let me provide an example.  I have a 
rowmatrix A that is nxm and I have two local matrices b and c.  b is mx1 and c 
is nx1.  In my spark job I wish to perform the following two computations


A*b


and


A^T*c


I don't think this is possible without being able to transpose a rowmatrix.  Am 
I correct?


Thanks,


Alex

________________________________
From: Reza Zadeh <r...@databricks.com>
Sent: Monday, January 12, 2015 1:58 PM
To: Alex Minnaar
Cc: u...@spark.incubator.apache.org
Subject: Re: RowMatrix multiplication

As you mentioned, you can perform A * b, where A is a rowmatrix and b is a 
local matrix.

>From your email, I figure you want to compute b * A^T. To do this, you can 
>compute C = A b^T, whose result is the transpose of what you were looking for, 
>i.e. C^T = b * A^T. To undo the transpose, you would have transpose C manually 
>yourself. Be careful though, because the result might not have each Row fit in 
>memory on a single machine, which is what RowMatrix requires. This danger is 
>why we didn't provide a transpose operation in RowMatrix natively.

To address this and more, there is an effort to provide more comprehensive 
linear algebra through block matrices, which will likely make it to 1.3:
https://issues.apache.org/jira/browse/SPARK-3434

Best,
Reza

On Mon, Jan 12, 2015 at 6:33 AM, Alex Minnaar 
<aminn...@verticalscope.com<mailto:aminn...@verticalscope.com>> wrote:

I have a rowMatrix on which I want to perform two multiplications.  The first 
is a right multiplication with a local matrix which is fine.  But after that I 
also wish to right multiply the transpose of my rowMatrix with a different 
local matrix.  I understand that there is no functionality to transpose a 
rowMatrix at this time but I was wondering if anyone could suggest a any kind 
of work-around for this.  I had thought that I might be able to initially 
create two rowMatrices - a normal version and a transposed version - and use 
either when appropriate.  Can anyone think of another alternative?


Thanks,


Alex

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