But if I put the return inside loop, method still wants me a return
statement.
2015-10-26 19:09 GMT+02:00 Ted Yu <yuzhih...@gmail.com>:
> bq. t = new Tuple2 <Integer, ArrayList<String>> (entry.getKey(),
> entry.getValue());
>
> The return statement is outside the loop.
> That was why you got one RDD.
>
> On Mon, Oct 26, 2015 at 9:40 AM, Yasemin Kaya <godo...@gmail.com> wrote:
>
>> Hi,
>>
>> I have *JavaRDD<List<Map<Integer, ArrayList<String>>>>* and I want to
>> convert every map to pairrdd, i mean
>> * JavaPairRDD<Integer,ArrayList<String>>. *
>>
>> There is a loop in list to get the indexed map, when I write code below,
>> it returns me only one rdd.
>>
>> JavaPairRDD<Integer,ArrayList<String>> mapToRDD =
>> IdMapValues.mapToPair(new
>> PairFunction<List<Map<Integer,ArrayList<String>>>, Integer,
>> ArrayList<String>>() {
>>
>> @Override
>> public Tuple2<Integer, ArrayList<String>> call(
>> List<Map<Integer, ArrayList<String>>> arg0)
>> throws Exception {
>> Tuple2<Integer, ArrayList<String>> t = null;
>> for(int i=0; i<arg0.size(); ++i){
>> for (Map.Entry<Integer, ArrayList<String>> entry :arg0.get(i).entrySet())
>> {
>> t = new Tuple2 <Integer, ArrayList<String>> (entry.getKey(),
>> entry.getValue());
>> }
>> }
>>
>> return t;
>> }
>> });
>>
>> As you can see i am using java. Give me some clue .. Thanks.
>>
>> Best,
>> yasemin
>>
>> --
>> hiç ender hiç
>>
>
>
--
hiç ender hiç
