You are probably trying to access the spring context from the executors after initializing it at the driver. And running into serialization issues.
You could instead use mapPartitions() and initialize the spring context from within that. That said I don't think that will solve all of your issues because you won't be able to use the other rich transformations in Spark. I am afraid these two don't gel that well, unless and otherwise all your context lookups for beans happen in the driver. Regards Sab On 13-Nov-2015 4:17 pm, "Netai Biswas" <mail2efo...@gmail.com> wrote: > Hi, > > I am facing issue while integrating spark with spring. > > I am getting "java.lang.IllegalStateException: Cannot deserialize > BeanFactory with id" errors for all beans. I have tried few solutions > available in web. Please help me out to solve this issue. > > Few details: > > Java : 8 > Spark : 1.5.1 > Spring : 3.2.9.RELEASE > > Please let me know if you need more information or any sample code. > > Thanks, > Netai > > > > -- > View this message in context: > http://apache-spark-user-list.1001560.n3.nabble.com/Spark-and-Spring-Integrations-tp25375.html > Sent from the Apache Spark User List mailing list archive at Nabble.com. > > --------------------------------------------------------------------- > To unsubscribe, e-mail: user-unsubscr...@spark.apache.org > For additional commands, e-mail: user-h...@spark.apache.org > >
