In DataFrames (and thus in 1.5 in general) this is not possible, correct?
> On 11.08.2016, at 05:42, Holden Karau <[email protected]> wrote: > > Hi Luis, > > You might want to consider upgrading to Spark 2.0 - but in Spark 1.6.2 you > can do groupBy followed by a reduce on the GroupedDataset ( > http://spark.apache.org/docs/1.6.2/api/scala/index.html#org.apache.spark.sql.GroupedDataset > > <http://spark.apache.org/docs/1.6.2/api/scala/index.html#org.apache.spark.sql.GroupedDataset> > ) - this works on a per-key basis despite the different name. In Spark 2.0 > you would use groupByKey on the Dataset followed by reduceGroups ( > http://spark.apache.org/docs/latest/api/scala/index.html#org.apache.spark.sql.KeyValueGroupedDataset > > <http://spark.apache.org/docs/latest/api/scala/index.html#org.apache.spark.sql.KeyValueGroupedDataset> > ). > > Cheers, > > Holden :) > > On Wed, Aug 10, 2016 at 5:15 PM, luismattor <[email protected] > <mailto:[email protected]>> wrote: > Hi everyone, > > Consider the following code: > > val result = df.groupBy("col1").agg(min("col2")) > > I know that rdd.reduceByKey(func) produces the same RDD as > rdd.groupByKey().mapValues(value => value.reduce(func)) However reducerByKey > is more efficient as it avoids shipping each value to the reducer doing the > aggregation (it ships partial aggregations instead). > > I wonder whether the DataFrame API optimizes the code doing something > similar to what RDD.reduceByKey does. > > I am using Spark 1.6.2. > > Regards, > Luis > > > > -- > View this message in context: > http://apache-spark-user-list.1001560.n3.nabble.com/Is-there-a-reduceByKey-functionality-in-DataFrame-API-tp27508.html > > <http://apache-spark-user-list.1001560.n3.nabble.com/Is-there-a-reduceByKey-functionality-in-DataFrame-API-tp27508.html> > Sent from the Apache Spark User List mailing list archive at Nabble.com. > > --------------------------------------------------------------------- > To unsubscribe e-mail: [email protected] > <mailto:[email protected]> > > > > > -- > Cell : 425-233-8271 > Twitter: https://twitter.com/holdenkarau <https://twitter.com/holdenkarau>
