You need to use a StringType. The CharType and VarCharType are there to
ensure compatibility with Hive and ORC; they should not be used anywhere
else.

On Thu, Nov 23, 2017 at 4:09 AM, 163 <hewenting_...@163.com> wrote:

> Hi,
>      when I use Dataframe with table schema, It goes wrong:
>
> val test_schema = StructType(Array(
>
>   StructField("id", IntegerType, false),
>   StructField("flag", CharType(1), false),
>   StructField("time", DateType, false)));
>
> val df = spark.read.format("com.databricks.spark.csv")
>   .schema(test_schema)
>   .option("header", "false")
>   .option("inferSchema", "false")
>   .option("delimiter", ",")
>   .load("file:///Users/name/b")
>
>
> The log is below:
> Exception in thread "main" scala.MatchError: CharType(1) (of class
> org.apache.spark.sql.types.CharType)
> at org.apache.spark.sql.catalyst.encoders.RowEncoder$.org$
> apache$spark$sql$catalyst$encoders$RowEncoder$$serializerFor(RowEncoder.
> scala:73)
> at org.apache.spark.sql.catalyst.encoders.RowEncoder$$anonfun$
> 2.apply(RowEncoder.scala:158)
> at org.apache.spark.sql.catalyst.encoders.RowEncoder$$anonfun$
> 2.apply(RowEncoder.scala:157)
>
> Why? Is this a bug?
>
> But I found spark will translate char type to string when using create
> table command:
>
>       create table test(flag char(1));
>       desc test:            flag string;
>
>
>
>
> Regards
> Wendy He
>



-- 

Herman van Hövell

Software Engineer

Databricks Inc.

hvanhov...@databricks.com

+31 6 420 590 27

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