Hi Jungtek,

Thanks for the response. It appears to be #1.
I will appreciate if you can share some sample command to submit the Spark 
application.?

From: Jungtaek Lim [mailto:kabhwan.opensou...@gmail.com]
Sent: Wednesday, May 06, 2020 8:24 PM
To: Vijayant Kumar <vijayant.ku...@mavenir.com.invalid>
Cc: user@spark.apache.org
Subject: [E] Re: Pyspark Kafka Structured Stream not working.


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Hi,

1. You seem to use DStream (Spark Streaming), not Structured Streaming.
2. I'm not familiar with pyspark, but looks like the error message is very 
clear - Kafka doesn't allow such name for "client.id<http://client.id>". The 
error message guides the naming rule, so you may need to be adopted with such 
convention. (e.g. no space)

Hope this helps,

Thanks,
Jungtaek Lim (HeartSaVioR)

On Wed, May 6, 2020 at 5:36 PM Vijayant Kumar 
<vijayant.ku...@mavenir.com.invalid<mailto:vijayant.ku...@mavenir.com.invalid>> 
wrote:
Hi All,

I am getting the below error while using Pyspark Structured Streaming from 
Kafka Producer.

20/05/06 11:51:16 ERROR ReceiverTracker: Deregistered receiver for stream 0: 
Error starting receiver 0 - kafka.common.InvalidConfigException: 
client.id<http://client.id> Python Kafka streamer is illegal, contains a 
character other than ASCII alphanumerics, '.', '_' and '-'

I am using the below code to get the messages:

    broker='vm105:2181'
    topic='Hello-Kafka'
    print 'broker topic is ',broker,topic
    kvs = KafkaUtils.createStream(ssc, \
                                  broker, \
                                  "Python Kafka streamer",{topic:1})

And my Submit command is like below :-
spark-submit --jars spark-streaming-kafka-0-8-assembly_2.11-2.4.4.jar 
test_kafka.py vm105:2181 Hello-Kafka

Can any one help me what am I missing. ?

Thanks,
Vijayant
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