No, because the final rdd is really the result of chaining 3 filter operations. They should all execute. It _should_ work like "rdd.filter(...).filter(..).filter(...)"
On Wed, Jan 20, 2021 at 9:46 AM Zhu Jingnan <jingnanzh...@gmail.com> wrote: > I thought that was right result. > > As rdd runs on a lacy basis. so every time rdd.collect() executed, the i > will be updated to the latest i value, so only one will be filter out. > > Regards > > Jingnan > > >
