Hi,
thanks but the reply but I think it does exactly what I want to avoid
(and what I'm currenlty doing) : Create a second temp file by reading
the inputsream into a new FileOutputStream.
I'm looking into the possibility to get the filepath (when exist) of the
FormFile, not the inpustream.
Mark Shifman wrote:
An action like this should do it:
public final class UploadAction extends Action {
public ActionForward execute( ActionMapping mapping, ActionForm form,
HttpServletRequest request, HttpServletResponse response)
throws Exception {
UploadForm theForm = (UploadForm) form;
FormFile file = theForm.getTheFile();
String fileName = file.getFileName();
try {
String filePath =
tempdir + "/" + fileName;
//retrieve the file data
InputStream stream = file.getInputStream();
//write the file to the file specified
OutputStream bos = new FileOutputStream(filePath);
int bytesRead = 0;
byte[] buffer = new byte[8192];
while ((bytesRead = stream.read(buffer, 0, 8192)) != -1) {
bos.write(buffer, 0, bytesRead);
}
bos.close();
//close the stream
stream.close();
} catch (Exception ex) {
throw ex;
}
file.destroy();
return (mapping.findForward("anywhereyouwant");
}
Laurent Duparchy wrote:
Hi,
My front-end program upload files and then forward the file path to
another server side program that handle them.
The problem is that I have to read the FormFile data and store it
into another temp file.
It would increase performances this data duplication and have access
directly to the Struts temp file.
I can't see how.
I understand that there is maybe no file at all, as a small size a
file will be stored in memory, but is the maybe existing underlying
FileItem avaiable in anyway ?
Laurent
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