super.prepare()?
Nils-H
On Thu, Aug 13, 2009 at 9:51 AM, Kishan
Paandy<kishanchellapaand...@spanservices.com> wrote:
>
> Hi Folks,
>
> I have a problem as below:
>
> 1)
> public abstract class AbstractBaseAction implements Preparable
> {
> public void prepare()
> {
> populateSomething();
> }
> }
>
> 2)
> public class MyAction1 extends AbstractBaseAction
> {
> ………
> }
>
> 3)
> public abstract class MyAction2 extends AbstractBaseAction implements
> Preparable
> {
> public void prepare()
> {
> doSomething();
> }
> }
>
> 4)
> public class MyAction3 extends MyAction2
> {
> ………
> }
>
> I have a design as above.
>
> The prepare() in AbstractBaseAction will do some common logic for MyAction1,
> MyAction2 & MyAction3.
> The prepare() in MyAction2 will do some common logic only for MyAction3.
> Only the prepare() in MyAction2 is being called for MyAction3. Since it’s
> being overridden.
> I want both the prepare() in AbstractBaseAction & MyAction2 to be called one
> after the other in the same order for MyAction3.
> How to achieve this?
> Please advice.
> Thank you.
> Regards,
> Kishan.G
> --
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>
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