First, let me assume that your Schema declares "AbstractClass" as the
substitutionGroup for "classA" and "classB" and not "AbstractElement"
like stated in your message. Then, you would write the following code:
RootDocument doc = RootDocument.Factory.newInstance();
RootDocument.Root root = doc.addNewRoot();
XmlObject xmlObject = root.addNewAbstractClass();
xmlObject = xmlObject.substitute(
ClassADocument.type.getDocumentElementName(),
ClassAType.type);
// You can now add stuff to xmlObject
Now the "doc" object will contain the document in the format you want.
The idea is that you need to use the method .substitute() to create a
document that uses substitution groups. XmlBeans doesn't look at the
fact that the element is abstract or that it has substitutions but
instead uses the simpler rule that "you need to call .substitute() if
you want to enable substitutions".
Radu
Hi,
Need some help in solving problems of abstract types. I have the
following elements:
<xs:element name="Root">
<xs:complexType>
<xs:sequence>
<xs:element ref="AbstractClass"/>
</xs:sequence>
</xs:complexType>
</xs:element>
<element name="AbstractClass" abstract="true">
<element name="classA" type="ClassAType"
substitutionGroup="AbstractElement">
<element name="classB" type="ClassBType"
substitutionGroup="AbstractElement">
I need an output XML of the form
<root>
<classA>...........</classA>
</root>
but i get the following:
<root>
<AbstractClass>
<classA>...........</classA>
</AbstractClass>
</root>
In the java code i have the following options
a) root.addNewAbstractClass();
b) root.setAbstractClass(XmlObject xmlObject);
I want to get only the implementation of the "AbstractClass" as the
sub-element of the "Root" element, how is it possible to achieve this.
Thanks in advance,
Cheers,
Satish
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