He means the XmlObject class which you'll find in the XmlBeans library.
-Albert
At 10:27 AM 11/6/2007, you wrote:
That sounds good but, I don´t have a XmlObject, I have a simple pojo (class
A) and i want to convert it to XmlObject, my class A have to implements
XmlObject ? How can I do this ??
Cezar Andrei wrote:
>
> It is possible, but a little less forward that using schema. Just use
> XmlObject, it handles all un-typed XML in XMLBeans.
>
> Use XmlObject xo = XmlObject.Factory.parse(xmlText) to load the xml into
> XmlObject.
> And String xmlText = xo.xmlText() to get back to xml.
>
> To navigate/read/modify the XmlObject without a schema, you have to use
> either the cursor xo.newCursor() or the DOM xo.newDomNode().
>
> Cezar
>
>> -----Original Message-----
>> From: imorales [mailto:[EMAIL PROTECTED]
>> Sent: Tuesday, November 06, 2007 8:50 AM
>> To: [email protected]
>> Subject: RE: xmlbeans beginner - help
>>
>>
>> Is there any way to get from Java classes without XML schema and vice
>> versa?
>>
>> Thanks.
>>
>> Schalk Neethling-4 wrote:
>> >
>> > You will more then likely have to start with a schema. So define your
>> > schema and the from this generate your XMLBean which will give you
>> object
>> > A, you can then populate object A using the set methods that will be
>> > generated and once you have the completed object you can invert it into
>> a
>> > XML string with one step by calling A.xmlText();
>> >
>> > HTH!
>> >
>> > Regards,
>> > Schalk Neethling
>> >
>> > -----Original Message-----
>> > From: imorales [mailto:[EMAIL PROTECTED]
>> > Sent: 06 November 2007 11:29 AM
>> > To: [email protected]
>> > Subject: xmlbeans beginner - help
>> >
>> >
>> > Hi is my first time using xmlbeans and I hava a couple of question, I
>> > explain
>> > my scenario and I would like someone to resolve my ignorance about
>> > xmlbeans.
>> >
>> > Well I hava a pojo class:
>> >
>> > ------------------------------------------
>> > public class A{
>> > private String b;
>> >
>> > public A(){}
>> >
>> > public String getB(){ return b;}
>> > public void setB(String b){this.b = b;}
>> > }
>> > ------------------------------------------
>> >
>> > I´m using a web service that takes one parameter (String), this
>> parameter
>> > is
>> > the XML associated to the class A. My question is how I can using
>> xmlbeans
>> > conver one object A to a XML and then to String. I have no schema to do
>> > this
>> > and I don´t know if is necessary.
>> >
>> > Thanks in advance.
>> >
>> > --
>> > View this message in context:
>> > http://www.nabble.com/xmlbeans-beginner---help-tf4756991.html#a13603299
>> > Sent from the Xml Beans - User mailing list archive at Nabble.com.
>> >
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