I've done the same thing. Basically, you need to get the SchemaParticle that corresponds to the XmlObject's schema type, then get the Type of that schema particle and finally, get the java class associated with that type, (via getJavaClass().)
I haven't actually tried this code so my apologies if it doesn't work... XmlObject testTypeExtension = test.getTest().getTypeExtensions().getExtensionArray()[0]; SchemaType testExtType = testTypeExtension.schemaType(); Class testExtClass = testExtType.getJavaClass(); //the Class you're interested in Hope it helps/works! cory -----Original Message----- From: cmoller [mailto:[EMAIL PROTECTED] Sent: Wednesday, November 14, 2007 11:05 AM To: [email protected] Subject: xsi:type and Java Class I am having trouble getting XmlBeans 1.0.4 to return the Java class I want from an XML document. The XSD defines a complex type containing a list of an abstract type. In another namespace I am defining a concrete extension of the abstract type. When I parse an xml document containing on of these lists, it returns references to the abstract type's class, not the concrete type. If I change the list to a list of anyType instead of the abstract type, I get back the expected class. Here are my XSD's: <xsd:schema xmlns:xsd="http://www.w3.org/2001/XMLSchema"; targetNamespace="http://domain/test"; xmlns:test="http://domain/test"; elementFormDefault="qualified"> <xsd:complexType name="testType"> <xsd:sequence> <xsd:element name="typeExtensions" minOccurs="0" type="test:testTypeExtensions"/> </xsd:sequence> </xsd:complexType> <xsd:complexType name="testTypeExtensions"> <xsd:sequence> <!--<xsd:element name="extension" type="test:testTypeExtension" maxOccurs="unbounded" minOccurs="0"></xsd:element>--> <xsd:element name="extension" type="xsd:anyType" maxOccurs="unbounded" minOccurs="0"></xsd:element> </xsd:sequence> </xsd:complexType> <xsd:complexType name="testTypeExtension" abstract="true"> <xsd:sequence/> </xsd:complexType> <xsd:element name="test" type="test:testType"/> </xsd:schema> ****XSD #2************************************** <xsd:schema xmlns:xsd="http://www.w3.org/2001/XMLSchema"; targetNamespace="http://domain/test/ext"; xmlns:test="http://domain/test"; elementFormDefault="qualified"> <xsd:import namespace="http://domain/test"; schemaLocation="test.xsd"></xsd:import> <xsd:complexType name="testTypeClientExtension"> <xsd:complexContent> <xsd:extension base="test:testTypeExtension"> <xsd:sequence> <xsd:element name="extensionElement" type="xsd:string"></xsd:element> </xsd:sequence> </xsd:extension> </xsd:complexContent> </xsd:complexType> </xsd:schema> **** JAVA CODE ****************** Here is the Java code that I am using to check the behavior. String xmlText = "<test:test xmlns:test=\"http://domain/test\"; xmlns:ext=\"http://domain/test/ext\"; xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\";><test:typeExtensions> <test:extension xsi:type=\"ext:testTypeClientExtension\"/></test:typeExtensions></test:test>" ; TestDocument test = (TestDocument) XmlObject.Factory.parse(xmlText); XmlObject testTypeExtension = test.getTest().getTypeExtensions().getExtensionArray()[0]; System.out.println("testTypeClientExtension.getClass().getName() - " + testTypeExtension.getClass().getName()); If I use anyType in the list in the xsd, the system out will display TestTypeClientExtension as the class. If I use TestTypeExtension, it will display TestTypeExtension. I want to get back an instance of the class based on the xsi:type. Thanks in advance for any help. -- View this message in context: http://www.nabble.com/xsi%3Atype-and-Java-Class-tf4807282.html#a13754000 Sent from the Xml Beans - User mailing list archive at Nabble.com. --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
