Hi again, I have another question: when XML Beans creates the java source files with a .xsd, is it possible to identify/know the java class name of the root element defined int the XML Schema? Because I must load this class at runtime i must know its name. Can you point me to a solution for this?
regards -------- Original-Nachricht -------- > Datum: Tue, 21 Oct 2008 17:52:00 -0700 > Von: "Radu Preotiuc-Pietro" <[EMAIL PROTECTED]> > An: "[email protected]" <[email protected]> > Betreff: RE: How to get Java Class of .xsd at runtime dynamically on-the-fly? > Well, this is somewhat a Java question also. Each Java class has to have a > classloader associated to it. The only way to get a Java class is to have > a classloader that is able to find the .class representation of a class and > load it. > > What this means for XMLBeans is that you need to compile the Schemas to > Java source (XmlBeans.compileXsd() or call "scomp" in a different process), > then compile and jar that source and then create a classloader that has > access to the freshly created .jar file. XmlBeans can't create classes without > source .java files and .jar files. > > What I should also point out is that you will only be able to use such > dynamically generated classes via reflection (since they don't exist when your > code is compiled), so this is why most people prefer to use DOM or > XmlCursor when dealing with Schemas that they only know about at runtime. The > XML > documents themselves will still be bound to a Schema, so you'll be able to > do Schema validation on them and get the actual Schema types. > > Radu > > > -----Original Message----- > > From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] > > Sent: Wednesday, October 08, 2008 2:23 AM > > To: [email protected] > > Subject: How to get Java Class of .xsd at runtime dynamically > > on-the-fly? > > > > Hello, > > > > I need the (freshly compiled?) Java Class from a .xsd at > > runtime on-the-fly. Without creating java source code files > > or .jar files. > > > > I tried org.apache.xmlbeans.XmlBeans.compileXsd() > > and > > org.apache.xmlbeans.XmlBeans.loadXsd() > > > > but I could not figure out how to spawn a Class from it. I > > tried to use the SchemaTypeSystem.getClassLoader() but this > > returns null always. I also tried SchemaType.getJavaClass() > > but somehow it does not work/I don't understand it/I don't > > know how to find the "root item Class" with it. > > > > Can you tell me: how do I get the Java Class of the "root > > item" within the .xsd at runtime (on-the-fly, without > > generating code files or .jar) ? > > > > regards! > > > > ali > > -- > > Ist Ihr Browser Vista-kompatibel? Jetzt die neuesten > > Browser-Versionen downloaden: http://www.gmx.net/de/go/browser > > > > --------------------------------------------------------------------- > > To unsubscribe, e-mail: [EMAIL PROTECTED] > > For additional commands, e-mail: [EMAIL PROTECTED] > > > > > > > > > --------------------------------------------------------------------- > To unsubscribe, e-mail: [EMAIL PROTECTED] > For additional commands, e-mail: [EMAIL PROTECTED] -- GMX Kostenlose Spiele: Einfach online spielen und Spaß haben mit Pastry Passion! http://games.entertainment.gmx.net/de/entertainment/games/free/puzzle/6169196 --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
