Thank you for your answer,

Indeed it now returns a valid result, though not the correct one.
Namely it returns:

 ...,rel(de,A,B),rel(para,A,C)...

which breaks the constraint that implies the 3rd argument
of one rel/3 to be the 2nd argument of the other rel/3.

It still seams an easy constraint to code in Prolog, as such
I'm finding it dificult to debug/solve.


Best Regards,
Peter


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