Hi Matt,
Thanks for your reply. The problem i am facing is using JPA. In my
applicationContext.xml, i wont specify anythig like
sessionFactory(datasource, HibernateTransactionManager et.,) which is
specified in Hibernate, instead i use entityManagerFactory and jpa based
transactionManager for JPA. There is also filter available for jpa but
eventhough it shows the LazyIni... error.
The main problem according to me is that i am using JPA but it is searching
for Hibernate configuration, i am unaware how to manage this one. This error
happens only when i use relational db. If i try to retrieve a single table
without any relation the whole data is retrieved and displayed in the view.
If u have any suggestion please offer.
This is the configuration i have done in app..Context.xml
<bean id="entityManagerFactory"
class="org.springframework.orm.jpa.LocalEntityManagerFactoryBean">
<property name="persistenceUnitName" value="ngsubsPersistence"/>
</bean>
<!-- Spring JPA Transaction Manager -->
<bean id="txManager"
class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerFactory"/>
</bean>
JPA filter
<filter>
<filter-name>jpaFilter</filter-name>
<filter-class>org.springframework.orm.jpa.support.OpenEntityManagerInViewFilter
</filter-class>
</filter>
<filter-mapping>
<filter-name>jpaFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
This shows same LazyIni... exception.
Regars
Thufail.
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