Thanks much. Figured I was getting hung up on the syntax. This is very helpful.
-- Christopher ----- Original Message ----- From: "Antoine Toulme" <[email protected]> To: [email protected] Sent: Thursday, July 21, 2011 9:38:28 PM Subject: Re: Dumb packaging question There's a dozen ways to spread the butter on the bread here. Here is my humble take: You can use the union construct: | package(:war).libs |= [LIB_A, LIB_B] If you have arrays of arrays, you can flatten: package(:war).libs |= [LIB_A, LIB_B, [LIB_C, LIB_D]].flatten To remove stuff selectively, use the delete method ? package(:war).libs.delete(LIB_C) The array class in Ruby is very interesting. I recommend keeping this page around: http://www.ruby-doc.org/core/classes/Array.html Arrays are Enumerable (think java.util.Collection) so this is a good read too: http://www.ruby-doc.org/core/classes/Enumerable.html On Thu, Jul 21, 2011 at 23:51, Christopher Tiwald <[email protected]>wrote: > This thing's driving me nuts, so I'm hoping for a little group wisdom. > I'm trying to package a WAR with some run-time libraries (i.e. unused > in compilation), but without other libraries (that throw tomcat errors > because tomcat already has them). > > i.e. I'm trying to do the following simultaneously: > > package(:war).libs += (LIBRARY_A, LIBRARY_B) > package(:war).libs -= (LIBRARY_C) > > The easiest way, of course, would be to just be write an array > (PACKAGE_THESE_LIBRARIES) that comprises all the correct libraries, > and then > use the 'with' method. On the other hand I've got something like 100 > libraries and this doesn't strike me as terribly elegant. I'm trying > to maximize understandability, readability, and repeatability, because > our maven pom.xml's had none of those qualities. > > Is there an obvious way to do this I'm missing here? > > -- Christopher >
