I resolved my problem by this way: this.from(m_from_folder_url) .split(new SplitExpression()) .process(new Processor()) .choice() .when(header("type").isEqualTo("add")) .to("direct:addEntry") .when(header("type").isEqualTo("modify")) .to("direct:modifyEntry"); from("direct:addEntry").aggregate(header("add"), new AggregationStrategy()).to(m_to_add_folder_url); from("direct:modifyEntry").aggregate(header("modify"), new AggregationStrategy()).to(m_to_modify_folder_url);
so this is a route which: - reads a file - splits it's entities - processes each entry separately - according to their nature aggregating processed entries to the appropriate file. kodcanavari wrote: > > Hi, > > I want to use an aggregator in order to aggregate all messages comming. > On my route i'm making a split with a splitter , then i process every > messages in parallel > and then i want to aggregate them all into a single file. > > Here is my snippet : > > > this.from(FROM_FOLDER).split(new LdapEntitySplitExpression()).process(new > LdapModifyProcessor()).aggregate(header("LDIFRecord"),new > LdapAggregationStrategy()).to(TO_FOLDER); > > > and inside LdapModifyProcessor() i do: > > exchange.getOut().setHeader("type", "LDIFRecord"); > > but it does not work. > > can anyone tellme how can i let every messages go thru aggregator? > > regards. > > > > -- View this message in context: http://old.nabble.com/How-to-aggregate-all-messages-into-a-single-message--tp25908234p26157808.html Sent from the Camel - Users mailing list archive at Nabble.com.