Hello Ade, Ron and Claus! Thanks for your responses. I assume that I can send/receive a message in SMX using Camel in this way:
first OSGI bundle: {code} from("direct:start") .to("nmr:orderEntryPreProcessor"); {code} second OSGI bundle: {code} from("nmr:orderEntryPreProcessor") .to("mock:end"); {code} But how it is possible to discover routes, deployed in another OSGI bundle to "extend" or modify a route dynamicly? I understood the following code will not work, if the route "nmr:orderEntryPreProcessor" is defined in another OSGI bundle: {code} Endpoint endpoint = exchange.getContext().hasEndpoint("nmr:orderEntryPreProcessor"); {code} Du you advice a solution like this: first OSGI bundle: {code} <bean id="orderEntryPreProcessorRoute" class="com.company.OrderEntryPreProcessorRoute" /> <osgi:service ref="orderEntryPreProcessorRoute"> <osgi:interfaces> <value>org.apache.camel.RoutesBuilder</value> </osgi:interfaces> <osgi:service-properties> <entry key="routeName" value="orderEntryPreProcessorRoute" /> </osgi:service-properties> </osgi:service> {code} and in the other bundle, I need a reference to the OSGI service registry and lookup the exported route (by service property because we export multiple routes). I don't know whether this works and how I can inject the OSGI service registry in a Spring managed bean. I assume, this is not the Spring application context... Thanks for your help, Christian -- View this message in context: http://camel.465427.n5.nabble.com/Camel-OSGI-and-container-wide-Camel-route-lookups-tp2269094p2473177.html Sent from the Camel - Users mailing list archive at Nabble.com.