See sample route snippet I wrote that worked for me: <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans"; xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"; xmlns:osgi="http://camel.apache.org/schema/osgi"; xmlns:beans="http://www.springframework.org/schema/beans"; xsi:schemaLocation=" http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.0.xsd http://camel.apache.org/schema/spring http://camel.apache.org/schema/spring/camel-spring.xsd http://camel.apache.org/schema/osgi http://camel.apache.org/schema/osgi/camel-osgi.xsd http://www.springframework.org/schema/osgi-compendium http://www.springframework.org/schema/osgi-compendium/spring-osgi-compendium.xsd http://www.springframework.org/schema/osgi http://www.springframework.org/schema/osgi/spring-osgi.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.0.xsd";>
<!-- ################# Rule Engines ############### --> <routeContext id="ruleEngines" xmlns="http://camel.apache.org/schema/spring";> <!-- preprocessor Rule Engine --> <route id="preprocessorRuleEngine"> <from uri="localRequestJMS:queue:preprocessorRuleEngine"/> <bean ref="rulesEngine" method="preprocess"/> <onException> <exception>java.lang.Exception</exception> <handled><constant>true</constant></handled> <to uri="localRequestJMS:queue:processorRuleEngine"/> </onException> </route> </routeContext> </beans> -- View this message in context: http://camel.465427.n5.nabble.com/Cannot-find-the-declaration-of-element-routeContext-tp2851604p3261545.html Sent from the Camel - Users mailing list archive at Nabble.com.
