Passing input fileName along the complete route

[shekher.awasthi]

Hi All,

While working i came across a requirements where i have to name the final
output file based on the input file
e.g
if the name of the input file is a.xml and i need to convert it to csv at
the end than the output file should be named as
 customoutput_a.xml.csv
like in my case i have the following route

<route id="demo">  
            
                   <from uri="{{demo.filePath}}"/>
                   
                   <choice>
                        <when>
                                <simple>${file:ext} ==  'csv'</simple>
                                <unmarshal>
                        <csv/>
                 </unmarshal>
                 
                <to uri="bean:converter?method=process" />
                <to uri="file://data/output?fileName=tmpXML.xml" />     
                  </when>
                   </choice>
                                  
               <to uri="{{demo.tmpXMLtoStandardXML}}"/>
               <to uri="file://data/output?fileName=3_StandardXML.xml" />
               <to uri="{{demo.StandardXMLToImpexXslFile}}"/>          
               <to uri="{{demo.targetXMLFile}}"/>   
            </route>  

now in such case in the last route point i have to name the file based on
the input file name, can any one help me how i can pass the input file name
throughout the route in camel so that i can extract the file name when
producing final output

Thanks in advance


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