Hi

You cannot do onException while doing onException, as this gets
complicated, and you could potentially end up in a endless loop or
whatever.
When the 2nd exception is detected Camel will log this at ERROR level
using a FatalFallbackErrorHandler.



On Fri, Feb 10, 2012 at 2:56 PM, atg roxx <atgr...@gmail.com> wrote:
> Hi ,
>
>
> I have a situation:
>
> In general in a camel when we have any exception in a route the onException
> is called.
>
> for example :
>
> onException definition:
> -------------------------------
> onException( MyException mye)
>               .process(new Processor() {
>  @Override
> public void process(Exchange exchange) throws Exception {
> SOP("got my exception");
>  }
>              });
>
> camel route:
> ---------------------
> from(jms:abc)
> .process(new Processor() {
>  @Override
> public void process(Exchange exchange) throws Exception {
> throw new MyException();
>  }
> });
>
>
>
> But if i throw an exception in process block of onException it is not
> getting caught in other  onException defined.
>
> for example:
>
> got and MyException-----------
> onException( MyException mye)
>               .process(new Processor() {
>  @Override
> public void process(Exchange exchange) throws Exception {
> // in processor block throwing mytestexception
>
>                                    throw new MyTestException();
>  }
>              });
>
>
> I have defined onException which can handle MyTestException. But this is
> not getting called :(
> -------------------------------------
> onException(  MyTestException myte)
>               .process(new Processor() {
>  @Override
> public void process(Exchange exchange) throws Exception {
>
> SOP("got my  MyTestException ");
>  }
>              });
>
>
> Could please anyone let me know why it is happening??? Also how can we
> achieve it.
>
>
> --cheers,
> atgroxx



-- 
Claus Ibsen
-----------------
FuseSource
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