On Wed, Jun 6, 2012 at 8:34 PM, pvenini <[email protected]> wrote:
> Hi,
> I've a situation where a route can throw many kinds of exceptions, say A, B,
> and C. If exception is class A I should let it pass; if it's any other kind
> of exception I should throw a new exception of class A.
>
> doTry().
> .
> .
> .
> doCatch(A.class).
> //Let it pass forward
> doCatch(Exception.class).
> throwException(new A("Some message", false)).
> stop();
>
> I'm having problems with the first situation (let the original exception A
> go forward); I tried to use handled(false) but it says it's deprecated, so I
> chose to use throwException(). However I' don't know how to get the original
> exception or if that's is impossible, how to get the text from the original
> exception and create a new one (tried to use exceptionMessage but I don't
> know how to convert a ValueBuilder to a String).
>
> Any help would be appreciated.
>
The caused exception is stored as a property on the Exchange with the
key Exchange.EXCEPTION_CAUGHT.
The simple expression can grab it easily
throwException(simple("${exception}")).
See details at
http://camel.apache.org/simple
> Pablo
>
> --
> View this message in context:
> http://camel.465427.n5.nabble.com/Rethrow-original-exception-tp5714087.html
> Sent from the Camel - Users mailing list archive at Nabble.com.
--
Claus Ibsen
-----------------
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