The exception is null because you use handled(true).
If you want to get the caused exception, then its stored as a property
on the exchange.
Exception cause = exchange.getProperty(Exchange.CAUGHT_EXCEPTION,
Exception.class);
On Tue, Aug 14, 2012 at 4:35 PM, Hilde <hilde.sch...@yahoo.de> wrote:
> Hello Readers!
>
> Inside the route combined with the DefaultErrorHandler we are using
> exception policies.
> When an exception is thrown that part is even called but the exception
> object is null:
>
> .onException(Exception.class).handled(true)
> .process(new Processor() {
> @Override
> public void process(Exchange exchange) throws Exception {
> exchange.getIn().setBody(exchange.getException()); // why
> exception is
> null ???
> }
> })
> .to("activemq:queue:" + JmsDestinations.QUEUE_LOG_SERVICE)
> .end()
>
> On the other side the jms consumer is used to take the exchange and finally
> logs the stack trace via
> camel log component:
>
> from("activemq:queue:" +
> JmsDestinations.QUEUE_LOG_SERVICE).routeId("logServiceRoute")
>
> .to("log:errorLog?level=ERROR&showAll=true&multiline=true&showStackTrace=true");
>
> What is the right way to log the stack trace into the log file by the camel
> log component? But
> take into account that JMS is in use.
>
> We are using version 2.10.0 .
>
> Cheers
> Hilde
>
>
>
> --
> View this message in context:
> http://camel.465427.n5.nabble.com/Exception-in-Exchange-is-null-tp5717324.html
> Sent from the Camel - Users mailing list archive at Nabble.com.
--
Claus Ibsen
-----------------
FuseSource
Email: cib...@fusesource.com
Web: http://fusesource.com
Twitter: davsclaus, fusenews
Blog: http://davsclaus.com
Author of Camel in Action: http://www.manning.com/ibsen
