Hi Lukasz, Nice to hear from you :-)
> For example my route is following: > process(new LoggingProcessor()) > or > processRef("loggingProcessor") As far as I know No, as interception for a given processor is not given at the DSL level. However what you could do is to make use of your own InterceptStrategy, something like: private static class LoggingProcessorInterceptor implements InterceptStrategy { @Override public Processor wrapProcessorInInterceptors(CamelContext context, ProcessorDefinition<?> definition, final Processor target, Processor nextTarget) throws Exception { if ("process[MyLoggingProcessor]".equals(definition.toString())) { return new Processor() { public void process(Exchange exchange) throws Exception { // do some interception logic here... exchange.getContext().createProducerTemplate().requestBody("mock:intercepted", exchange.getIn().getBody()); // and then continue with the given target target.process(exchange); } }; } return target; } } Where your LoggingProcessor is given as something like: private static class LoggingProcessor implements Processor { @Override public void process(Exchange exchange) throws Exception { // your logging logic } @Override public String toString() { return "MyLoggingProcessor"; } } And then add this InterceptorStrategy to your Camel context: context.addInterceptStrategy(new LoggingProcessorInterceptor()); > Also, is it's even possible to use interceptSendToEndpoint with bean or > beanRef DSL elements? Yes as interceptSendToEndpoint can be used for any kind of Endpoint including the bean endpoint: interceptSendToEndpoint("bean:hello?method=camel").to("mock:intercepted"); Also note that you could make use of wildcard or regular expressions while specifying the endpoint uri: http://camel.apache.org/intercept.html Babak -- View this message in context: http://camel.465427.n5.nabble.com/Intercept-processor-bean-tp5717639p5717664.html Sent from the Camel - Users mailing list archive at Nabble.com.