Thanks Arnaud for the reply
I feel I was not able to describe myself fully in my last post. In the
example below I am picking a xml file src/data/message1.xml and putting it
in a queue test.MyQueue.
After listen this using camel, as shown in camel context and pass this
message in target/test folder. Here I am getting exchangeId as file name
rather than name "testmesage" that I specified.
Integration test class is :
public class AppTest
extends TestCase
{
protected CamelContext camelContext;
private static final String URI = "activemq://queue:test.MyQueue" ;
BrokerService broker;
public void setUp() throws Exception{
ApplicationContext applicationContext = new
ClassPathXmlApplicationContext("META-INF/spring/camel-context.xml");
camelContext =
(CamelContext)applicationContext.getBean("camel");
broker = new BrokerService();
broker.addConnector("tcp://localhost:61616");
broker.start();
}
protected void sendTo(String uri,String message) throws Exception {
ProducerTemplate producerTemplate =
camelContext.createProducerTemplate();
Exchange exchange = new DefaultExchange(camelContext,
ExchangePattern.InOut);
exchange.getIn().setBody(message);
Message camelMessage = exchange.getIn();
camelMessage.setHeader(Exchange.FILE_NAME, "testmesage");
System.out.println(exchange.getExchangeId());
System.out.println(exchange.getIn().getMessageId());
producerTemplate.send(uri, exchange);
Thread.sleep(1000);
}
public void testMeth() throws Exception {
File file = new File("src/data/message1.xml");
FileReader fileReader = new FileReader(file);
BufferedReader bufferedReader = new BufferedReader(fileReader);
String message= null;
String str=null;
while( ( (str=bufferedReader.readLine()) != null)) {
message=message+str;
}
sendTo(URI, message);
}
public void tearDown() {
}
}
camel route in camel-context.xml is :
<camelContext id="camel" xmlns="http://camel.apache.org/schema/spring";>
<route>
<from uri="jms:test.MyQueue"/>
<to uri="file://target/test?noop=true/>
</route>
</camelContext>
Thanks
Saurabh
thecafetechno.com
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