Hi
In your code there may be a bug in doCatch I am not sure. Though can
you try adding a extra step after the process in the doCatch.
doCatch(...)
.process( ...)
.to("log:foo") <-- add extra step
.end()
Also see this FAQ about using getOut or getIn
http://camel.apache.org/using-getin-or-getout-methods-on-exchange.html
On Fri, Nov 16, 2012 at 11:25 AM, maxence.dewil <[email protected]> wrote:
> Hi,
>
> tested with camel 2.10.1 and 2.10.2 :
>
> *When I turn the route :*
>
> from("cxf:/myWebService?serviceClass=com.x.MyWebService").routeId("MyRoute")
> .process(new Processor() {
> @Override
> public void process(Exchange exchange) throws Exception {
> exchange.getOut().setBody(new Output());
> }});
>
> *into :*
>
> from("cxf:/myWebService?serviceClass=com.x.MyWebService").routeId("MyRoute")
> .doTry()
> .process(new Processor() {
> @Override
> public void process(Exchange exchange) throws Exception {
> throw new IllegalStateException();
> }});
> .doCatch(IllegalStateException.class)
> .process(new Processor() {
> @Override
> public void process(Exchange exchange) throws Exception {
> exchange.getOut().setBody(new Output());
> }});
> .end();
>
> *Then the response body of myWebService is empty.*
>
> Is it possible that my route returns something in a doCatch() ?
>
> Any help would be appreciated
>
>
>
> --
> View this message in context:
> http://camel.465427.n5.nabble.com/doCatch-returns-null-tp5722851.html
> Sent from the Camel - Users mailing list archive at Nabble.com.
--
Claus Ibsen
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