Hi all, I need to read a xml file: <? xml version = "1.0" encoding = "UTF-8"> <data> <name> XXXXX </ name> <lastname> YYYYY </ lastname> <address> ZZZZZZ </ address> </ data>
This information needs to be stored in a queue ActiveMQ. I am working with spring. this is file: <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://camel.apache.org/schema/spring http://camel.apache.org/schema/spring/camel-spring.xsd"> <bean id="jms" class="org.apache.camel.component.jms.JmsComponent"> <property name="connectionFactory"> <bean class="org.apache.activemq.ActiveMQConnectionFactory"> <property name="brokerURL" value="vm://localhost" /> </bean> </property> </bean> <bean id="downloadLogger" class="bbr_camel.bbr_camel.DownloadLogger"/> <camelContext xmlns="http://camel.apache.org/schema/spring"> <route> <from uri="file:Inbox?noop=true"/> <process ref="downloadLogger"/> <to uri="jms:queue:ficha"/> </route> </camelContext> </beans> call from a main, public class FileCopierWithCamel { public static void main(String args[]) throws Exception{ try { final ApplicationContext context = new ClassPathXmlApplicationContext("context-jms.xml"); } catch (Exception e) { System.out.println("Ex: " + e); e.printStackTrace(); } } } but does not keep in line, no errors occur, eventually not work. anyone has any idea of the problem. Thank you. -- View this message in context: http://camel.465427.n5.nabble.com/read-xml-file-to-be-sent-to-a-queue-tp5724604.html Sent from the Camel - Users mailing list archive at Nabble.com.