Hi all,
I need to read a xml file:

<? xml version = "1.0" encoding = "UTF-8"> 
<data>
<name> XXXXX </ name>
<lastname> YYYYY </ lastname>
<address> ZZZZZZ </ address>
</ data>

This information needs to be stored in a queue ActiveMQ. I am working with
spring. this is file:

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans";
        xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance";
        xsi:schemaLocation="http://www.springframework.org/schema/beans 
        http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
        http://camel.apache.org/schema/spring
        http://camel.apache.org/schema/spring/camel-spring.xsd";>

        <bean id="jms" class="org.apache.camel.component.jms.JmsComponent">
                <property name="connectionFactory">
                <bean class="org.apache.activemq.ActiveMQConnectionFactory">
                <property name="brokerURL" value="vm://localhost" />
                </bean>
                </property>
        </bean>
        
        <bean id="downloadLogger" class="bbr_camel.bbr_camel.DownloadLogger"/>
        
        <camelContext xmlns="http://camel.apache.org/schema/spring";>
                <route>
                        <from uri="file:Inbox?noop=true"/>
                        <process ref="downloadLogger"/>
                        <to uri="jms:queue:ficha"/>
                </route>
        </camelContext>
</beans>

call from a main,

public class FileCopierWithCamel {

           public static void main(String args[]) throws Exception{
try {
                                final ApplicationContext context = new
ClassPathXmlApplicationContext("context-jms.xml");
                        } catch (Exception e) {
                                System.out.println("Ex: " + e);
                                e.printStackTrace();
                        }
           }
        }


but does not keep in line, no errors occur, eventually not work.

anyone has any idea of ​​the problem.

Thank you.




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