Hi Guys,
here is my situation:
1. We need to consume an external REST Web Service exposed and maintained by
3-rd party;
2. This service accepts POST requests with XML payload based on which it
creates a resource;
3. In our current Camel route we call a REST client bean like this:
...
<to uri="velocity://velocity/custody-trade-request.vm" />
<log message="XML payload to send to REST WS:${body}" />
*<bean ref="restClient" method="createResource('${body}')" />*
and here is the restClient config (in the sping context):
<jaxrs:client id="restClient"
address="http://localhost:8080/my-rest-service/services";
serviceClass="com.my.services.rs.client.ExampleResource" >
<jaxrs:headers>
<entry key="Charset" value="UTF-8"/>
<entry key="Accept" value="application/xml"/>
</jaxrs:headers>
</jaxrs:client>
4. The com.my.services.rs.client.ExampleResource is just an interface and
looks like this:
public interface ExampleResource {
@POST
@Path(value = "/resources/")
@Produces(MediaType.APPLICATION_XML)
public String createExampleResource(String exampleResourceXML);
}
That all works fine as it is.
However we want to use the cxfrs Camel component instead and replace the
line in bold above with something like this:
*<to uri="cxfrs://bean://restClient"/>*
I have gone through the example in the cxfrs component's doc but coudn't
understand how could i only create cxf:rsClient and use this in my route?
Thank you for your help.
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