Hi, I have a simple question about parsing xml and performance. Actually my route is like this :
from("endpointIn") .convertBodyTo(String.class)// .unmarshal().jaxb("com.groupemb.entite.search.compario.in")// .process(...) where com.groupemb.entite.search.compario.in refers to a jaxb.index file which refers to a java class named ResponseCompario.java It works fine but i was wondering, is this route more performant ?: from("endpointIn") .convertBodyTo(ResponseCompario.class)// .process(...) NB: The xml files are pretty big. Best regards, -- View this message in context: http://camel.465427.n5.nabble.com/Parsing-XML-Performance-tp5727867.html Sent from the Camel - Users mailing list archive at Nabble.com.