Hi
I suggest you remove the streamCaching() and to("log:servlet") from your route.
Current streamCaching doesn't support to caching the Servlet request input
stream.
--
Willem Jiang
Red Hat, Inc.
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On Thursday, May 9, 2013 at 9:22 AM, crmanoj wrote:
> Hi,
>
> I am trying to upload a file to the server from client using
> multipart/form-data. The server endpoint is a camel-servlet endpoint. I am
> able to get the httprequestbody from the call using (in.headers), to parse
> the form data and uploaded file data i'm using commons-fileupload( streaming
> api <http://commons.apache.org/proper/commons-fileupload/streaming.html> )
> library. Though the request is a multipart, I am unable to get the fileitems
> from the function call. Here is the codesnippet used to get the item
> (iter.hasNext() always returns false).
>
> HttpServletRequest request = (HttpServletRequest)
> headers.get(Exchange.HTTP_SERVLET_REQUEST);
>
> // Check if the request is actually a multipart/form-data request.
> LOG.info (http://LOG.info)("IS Mulipart: " +
> ServletFileUpload.isMultipartContent(request));
> if (!ServletFileUpload.isMultipartContent(request))
> {
> return "No Data found";
> }
> // Create a new file upload handler
> ServletFileUpload upload = new ServletFileUpload();
> FileItemIterator iter = upload.getItemIterator(request);
> LOG.info (http://LOG.info)("iter has next: " + iter.hasNext());
>
> My Camel route looks like below:
>
> from("servlet:///addContent").streamCaching()
> .to("log:servlet").beanRef("sampleProcessor");
>
> My camel Servlet component definition goes as below:
>
> <service ref="camelServlet">
> <interfaces>
> <value>javax.servlet.Servlet</value>
> <value>org.apache.camel.component.http.CamelServlet</value>
> </interfaces>
> <service-properties>
> <entry key="alias" value="/camel/services" />
> <entry key="matchOnUriPrefix" value="true" />
> <entry key="servlet-name" value="CamelServlet"/>
> </service-properties>
> </service>
>
> <osgi:reference id="servletref"
> interface="org.apache.camel.component.http.CamelServlet">
> <osgi:listener bind-method="register" unbind-method="unregister">
> <ref bean="httpRegistry" />
> </osgi:listener>
> </osgi:reference>
>
> <bean id="httpRegistry"
> class="org.apache.camel.component.servlet.DefaultHttpRegistry">
> </bean>
> <bean id="servlet"
> class="org.apache.camel.component.servlet.ServletComponent">
> <property name="httpRegistry" ref="httpRegistry" />
> </bean>
>
> This project is run in fuse-esb-7.1.0.fuse-047 using camel version: 2.9.
> JDK: 1.6.
>
> Could anyone guide me to separate the form parameters and file data using
> servlet endpoint?
>
> Thanks in Advance!
>
>
>
> --
> View this message in context:
> http://camel.465427.n5.nabble.com/Using-camel-servlet-with-Multipart-unable-to-fetch-the-file-tp5732204.html
> Sent from the Camel - Users mailing list archive at Nabble.com
> (http://Nabble.com).
