Hi The multicast has built-in aggregation so that is much easier to use. So remove the aggregate from the route. And add the aggregation strategy to the multicast directly.
On Fri, Jul 26, 2013 at 10:38 AM, FritzGerald <[email protected]> wrote: > Hello, > > i'm new to camel and i'm having a problem using the multicast option. I > defined four beans that do some calculations. They receive the number 5 and > then > > add, subtract and so on. The 5 is being sent by the bean giveMeNumber. > The problem is that in the end I don't receive the result I expect. > > This is how my route looks like: > > context.addRoutes(new RouteBuilder() { > public void configure() { > > from("bean:giveMeNumber?method=giveNumber") > .multicast() > .parallelProcessing() > > > .to("bean:add?method=calculate") > > .to("bean:subtract?method=calculate") > > .to("bean:multiply?method=calculate") > > .to("bean:divide?method=calculate") > > .aggregate(new > MyAggregator()).body().completionSize(4) > .to("bean:drucker?method=print"); > > } > }); > > All beans act on a Double. Do I need the "MyAggregator" to aggregate 4 > Doubles or is this something Camel can do on its own ? > > And there's my problem. If, for example, my bean "giveNumber" returns the > number 5 the output of the printer should be like "10 0 25 1" (because > 5+5=10, > > 5-5=0, 5*5=25, 5/5=1). But my output is "5 5 5 5". So it seems like my > aggregator isn't appended to my .to()-beans but to my from()-bean. Is there > a > > mistake in the route-definition or do you have any ideas what my problem > could be? > > Thanks for your help, > > FritzGerald > > > > -- > View this message in context: > http://camel.465427.n5.nabble.com/problem-with-aggregating-multicast-tp5736283.html > Sent from the Camel - Users mailing list archive at Nabble.com. -- Claus Ibsen ----------------- Red Hat, Inc. Email: [email protected] Twitter: davsclaus Blog: http://davsclaus.com Author of Camel in Action: http://www.manning.com/ibsen
