from("direct:b").routeId("2")
.errorHandler(noErrorHandler())
.process(new ThrowingExceptionProcessor());
Best,
Christian
-----------------
Software Integration Specialist
Apache Camel committer: https://camel.apache.org/team
V.P. Apache Camel: https://www.apache.org/foundation/
Apache Member: https://www.apache.org/foundation/members.html
https://www.linkedin.com/pub/christian-mueller/11/551/642
On Thu, Sep 12, 2013 at 4:29 PM, fbarbat <fbar...@gmail.com> wrote:
> Hi,
>
> I have these routes:
>
> from("direct:a").routeId("1")
> .onException(Exception.class).handled(true).to("direct:d").end()
> .to("direct:b").to("direct:c");
>
> from("direct:b").routeId("2").process(new ThrowingExceptionProcessor());
> from("direct:c").routeId("3").process(new OkProcessor());
>
> from("direct:d").routeId("4").process(new ExceptionProcessor());
>
> Let's suppose a message comes to route 1. If ThrowingExceptionProcessor
> throws an exception I would expect that the exception would be handled by
> the onException clause. However, it looks like the exception is propagated
> directly to the consumer ("direct:a"). How can I force the exceptions
> thrown
> inside "child routes" to be managed by the onException clause?
>
> Thanks.
>
>
>
> --
> View this message in context:
> http://camel.465427.n5.nabble.com/DefaultErrorHandler-and-nested-routes-tp5739261.html
> Sent from the Camel - Users mailing list archive at Nabble.com.
>
