I am trying to get only only the last message from 10 messages passed to queue. I read messages in XML format and extracted the dat and passed to activemq.
My message in activemq in the form Sending message Broadcast Message 37 <p>Received on : Mon Nov 11 15:41:2 5 IST 2013EURUSR1.358EUR/USR97.1296.70597.296.5650.4150.428.50.21EUR/USR1.60551. 60971.61011.6043-0.0041-0.268.50.21EUR/USR0.90540.90280.90670.90260.00250.288.50 .21EUR/USR0.94430.94280.94520.9410.00150.168.50.22EUR/USR1.03311.03131.03361.030 70.00180.178.50.21EUR/USR0.83020.83040.83160.827-0.0003-0.038.50.21EUR/USR6.1219 6.12056.12216.11790.00140.028:48 Help me to resolve Thanks Raji -- View this message in context: http://camel.465427.n5.nabble.com/How-to-retrieve-only-the-last-message-from-10-messages-passed-to-queue-tp5743024.html Sent from the Camel - Users mailing list archive at Nabble.com.
