You can use pollEnrich with a file: endpoint.
Henrique Viecili
On 27 November 2013 12:10, Bilgin Ibryam <bibr...@gmail.com> wrote:
> Hi Lothar,
>
> One possible approach would be to have a processor that receives the
> notification and creates dynamically a route based on the notification
> header to poll the directory.
>
> Here is some pseudo code:
>
> from(jms)
> .process(new Processor() {
> @Override
> public void process(Exchange exchange) throws
> Exception {
>
> exchange.getContext().addRoutes(new RouteBuilder() {
>
> public void configure() {
>
> from("file://" + header + ? +
> sendEmptyMessageWhenIdle=true)
>
> .to(somewhere)
> }
>
> }
> })
>
>
> The route could send an empty message when all the files are processed,
> allowing you to detect that and stop it as shown here
>
> http://camel.apache.org/how-can-i-stop-a-route-from-a-route.html
>
> HTH,
>
>
>
> On Tue, Nov 26, 2013 at 10:39 PM, Lothar Werzinger <lot...@tradescape.biz
> >wrote:
>
> > Hi,
> >
> > I would like to create a route that responds to a trigger (e.g. from a
> > queue) and then scans a directory which path is given as a header
> attribute
> > in the trigger message where I can then route the found files through a
> set
> > of other components.
> >
> > However if I connect a file component to an input component it
> > automatically becomes an output component, so the "direct approach"
> > from(...).to(file://...).to(...) obviously does not work.
> >
> > How can I create such a route?
> >
> > Thanks in advance!
> > --
> >
> > Lothar Werzinger
> >
> > Principal Architect
> >
> > Tradescape, Inc. - Enabling Efficient Digital Marketplaces
> >
> > +1-650-931-6719 (direct)
> >
> > +1-800-697-6068 (main) Ext. 116
> >
> > lot...@tradescape.biz
> >
> > http://www.tradescape.biz
> >
> > --
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> > -
> >
>
>
>
> --
> Bilgin Ibryam
>
> Apache Camel & Apache OFBiz committer
> Blog: ofbizian.com
> Twitter: @bibryam <https://twitter.com/bibryam>
>
> Author of Instant Apache Camel Message Routing
> http://www.amazon.com/dp/1783283475
>
