Re: camel cxfrs with swagger.

[Matt Raible]

Here's how I did it.

Application.java (to register Camel's servlet):
----
import org.apache.camel.component.servlet.CamelHttpTransportServlet;
import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.EnableAutoConfiguration;
import org.springframework.boot.builder.SpringApplicationBuilder;
import 
org.springframework.boot.context.embedded.ConfigurableEmbeddedServletContainer;
import 
org.springframework.boot.context.embedded.EmbeddedServletContainerCustomizer;
import org.springframework.boot.context.embedded.ErrorPage;
import org.springframework.boot.context.embedded.ServletRegistrationBean;
import org.springframework.boot.context.web.SpringBootServletInitializer;
import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.ComponentScan;
import org.springframework.context.annotation.Configuration;
import org.springframework.http.HttpStatus;

@Configuration
@ComponentScan
@EnableAutoConfiguration
public class Application extends SpringBootServletInitializer {
        private static final String CAMEL_URL_MAPPING = "/rest/*";
        private static final String CAMEL_SERVLET_NAME = "CamelServlet";

        public static void main(String[] args) {
                SpringApplication.run(Application.class, args);
        }

        @Override
        protected SpringApplicationBuilder configure(SpringApplicationBuilder 
application) {
                return application.sources(Application.class);
        }

        @Bean
        public ServletRegistrationBean servletRegistrationBean() {
                ServletRegistrationBean registration =
                                new ServletRegistrationBean(new 
CamelHttpTransportServlet(), CAMEL_URL_MAPPING);
                registration.setName(CAMEL_SERVLET_NAME);
                return registration;
        }

        @Bean
        public EmbeddedServletContainerCustomizer containerCustomizer() {
                return new EmbeddedServletContainerCustomizer() {
                        @Override
                        public void 
customize(ConfigurableEmbeddedServletContainer container) {
                                ErrorPage error401Page = new 
ErrorPage(HttpStatus.UNAUTHORIZED, "/401.html");
                                ErrorPage error404Page = new 
ErrorPage(HttpStatus.NOT_FOUND, "/404.html");
                                ErrorPage error500Page = new 
ErrorPage(HttpStatus.INTERNAL_SERVER_ERROR, "/500.html");

                                container.addErrorPages(error401Page, 
error404Page, error500Page);
                        }
                };
        }
}

SwaggerConfig.java:
----
@Configuration
public class SwaggerConfig implements EnvironmentAware {

    private RelaxedPropertyResolver propertyResolver;

    @Override
    public void setEnvironment(Environment environment) {
        this.propertyResolver = new RelaxedPropertyResolver(environment, 
"swagger.");
    }

    /**
     * Swagger Camel Configuration
     */
    @Bean
    public ServletRegistrationBean swaggerServlet() {
        ServletRegistrationBean swagger = new ServletRegistrationBean(new 
SpringRestSwaggerApiDeclarationServlet(), "/swagger/*");
        Map<String, String> params = new HashMap<>();
        params.put("base.path", "https://localhost:8443/rest";);
        params.put("api.title", propertyResolver.getProperty("title"));
        params.put("api.description", 
propertyResolver.getProperty("description"));
        params.put("api.termsOfServiceUrl", 
propertyResolver.getProperty("termsOfServiceUrl"));
        params.put("api.license", propertyResolver.getProperty("license"));
        params.put("api.licenseUrl", 
propertyResolver.getProperty("licenseUrl"));
        swagger.setInitParameters(params);
        return swagger;
    }

}

application.properties:
----
# Swagger
swagger.title = My API
swagger.description = A description.
swagger.termsOfServiceUrl = http://yourcompany.com/terms.html
swagger.contact =
swagger.license = Apache 2.0
swagger.licenseUrl = http://www.apache.org/licenses/LICENSE-2.0.html

Hope this helps,

Matt

On Fri, Oct 17, 2014 at 3:18 AM, atg roxx <atgr...@gmail.com> wrote:
Hi Team,

I am using camel 2.14 and I am trying to expose rest endpoint using CXFRS
and want to use swagger to expose the rest api.


I am able to expose my rest service using cxfrs as described here :
http://camel.apache.org/cxfrs.html

My application is not a web application, and I am using spring and spring
boot for my application.

So I dont have web.xml in my case.

Now for Integrating with Swagger, I looked at
http://camel.apache.org/swagger.html

but it uses web.xml for it.

Is there anyways we can do it without using web.xml.

I looked at the exmple "camel-example-servlet-rest-tomcat" (
http://camel.apache.org/examples.html) explaining swagger integration with
 Camel, but here too web application is used for example i.e web.xml for
this integration.


Could anyone suggest how can we integrate swagger without use  of web.xml


-Cheers,
atg roxx



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