Hi all, I've been experimenting with camel-hystrix and wanted to check what the expected (or correct) behaviour should be when the Hystrix circuit is open.
Looking at HystrixProcessorCommand.getFallback(), the fallback command is only ever run if a prior exception was encountered. However, when the circuit is in the open state, I'd expect a 'short-circuit' and the default action would be to just invoke the fallback command (if configured). I'm basing my assumptions on the Hystrix docs: https://github.com/Netflix/Hystrix/wiki/How-it-Works Is this a bug? Or am i misunderstanding how it should work in Camel? -- James
