I have also found it a bit difficult to get a straight answer on this but my understanding at this point is that if the exchange gets to the end of the route and is an InOut, the Out from the last endpoint goes back to the 'from' starting point.
http://camel.apache.org/request-reply.html -Steve > -----Original Message----- > From: Peter Nagy (Jr) <pn...@gratex.com> > Sent: Friday, December 14, 2018 10:27 AM > To: users@camel.apache.org > Subject: understanding InOut > > I still don't quite grok how InOut works. When I set the exchange pattern to > InOut, what exactly will happen? Will the *next* processor reply to the > previous one? If so, how? If so, how does the previous processor act on the > reply? Or is the InOut just about 1 Processor? If so, can e.g. a Processor > block > until a split is reaggregated? > > I'm trying to find some documentation on this that would explain these > details but I didn't find much. The request-reply page is brief and uses > mocks. > > As a real world bonus - I'm running a mongodb aggregation pipeline splitting > and streaming and would need to fire just 1 exchange further down the > route when the whole aggregation is finished. I'm doing > > .to("mongodb3://...") > .split(..).streaming() > ... > .aggregate(..) > .hereINeed1exchange; > > I recently found out that split can take an aggregator as argument, would that > solve this case? How exactly does that work? > > -- > To reach a goal one has to enjoy the journey.
