How to get route Exception in a processor with camel+rabbitmq

[Alessandro Hoss]

Hello guys,

I've a route with onException, which sends the message to rabbitMQ, and
another route listening rabbit to call a processor and get the exception
thrown. I'm able to reach this processor, but i'm not able to get the
exception thrown.

I've tried with the <handled> property set to false, and with
transferException=true query param on the endpoint uri's, but without luck.

On the "processorToGetExceptionData" i have tried both
"exchange.getException()" and
"exchange.getProperty(Exchange.EXCEPTION_CAUGHT, Exception.class)", again
without luck.

Above are the (simplified) routes definitions:

<route id="route1">
    <from uri="rabbitmq:myExchange?queue=start&amp;routingKey=start"/>
    <onException>
            <exception>java.lang.Exception</exception>
            <redeliveryPolicy maximumRedeliveries="2"
redeliveryDelay="5000" retryAttemptedLogLevel="WARN"/>
            <handled>
                <constant>true</constant>
            </handled>
            <setHeader headerName="rabbitmq.ROUTING_KEY">
                <constant>errorMessage</constant>
            </setHeader>
            <to uri="rabbitmq:myExchange?skipQueueDeclare=true"/>
    </onException>
    <process ref="processorThatThrowsSomeException"/>
     <to uri="anyEndpoint" />
</route>

<route id="route2">
    <from
uri="rabbitmq:myExchange?queue=errorMessage&amp;routingKey=errorMessage"/>
    <process ref="processorToGetExceptionData"/>
    <to uri="anotherEndpoint"/>
</route>

Any ideas on what could be wrong ?

Thanks in advance,
Alessandro Hoss