Hi, I have a routetemplate as follows:
routeTemplate("processortemplate") .templateParameter("out") .from("direct:in") .process("MyProcessor") .to("{{out}}"); This works. The processor is registered an the called by reference. Now I added a constructor argument to the processor and I tried to call it like this: routeTemplate("processortemplate") .templateParameter("processerParam") .templateParameter("out") .from("direct:in") .process(new MyProcessor("{{processorParam}}")) .to("{{out}}"); This doesn't work, because the parameter of the processor is parsed before the template parameter is parsed. Result is that the parameter {{myProcessorParam}} is passed as literal param. I tried to come with up something like this: routeTemplate("processortemplate") .templateParameter("processerparam") .templateParameter("out") .templateBean("MyProcessor") .typeClass("com.foo.MyProcessor") .property("processerparam", "{{processerparam}}") .end() .from("direct:in") .to("bean:MyProcessor?method=process") .to("{{out}}"); But this didn't pass the parameter as well. As a workaround I set constructor argument as a header and then get the header within the processor. Question: Is there a way to pass constructor arguments to a processor in another way? I couldn't find anything at the routeTemplate page on how to handle processors. Raymond