Ben Have a look at the recent xsl mailing list archives... I have been having *exactly* the same problems (choosing a sort selection dynamically) and there were a number of very helpful answers from the folks there!
http://www.mulberrytech.com/xsl/xsl-list Derek PS and yes, <xsl:param> must *always* come before your template matches - suggest you find some some good reading material on XSL and get to grips with the basics... I reccommend Michael Kay's XSLT Programmer's Reference. >>> [EMAIL PROTECTED] 2004/07/19 02:43:53 AM >>> Hi Adam, Thanks for the reply. I changed the sitemap (That looks pretty close to another variation I tried). My output.xsl Already had <xsl:param name="sort"/> But it still didn't work. Then I reordered some stuff to what you suggested (don't know if you meant for me to re-order it) <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";> <xsl:template match="/"> <xsl:param name="sort"/> Became <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";> <xsl:param name="sort"/> <xsl:template match="/"> And it now says: "Reports - sort order = date." Or "Reports - sort order = number." So <xsl:value-of select="$sort"/> works nicely. You star! So is it best to have use-request-parameters set to false and pass the single parameter in (in terms of ability to cache the form)? I guess it can use the cached version if that one parameter remains constant, rather then the whole set of parameters? One problem persists: It still doesn't actually sort the table. <xsl:for-each select="data/reports/*"> <xsl:sort select="$sort"/> <!-- blah --> </xsl:for-each> Is my <xsl:sort /> tag correct? (I presume not). Thank you again, I am at least a lot closer. Ben. -----Original Message----- From: Adam Walsh [mailto:[EMAIL PROTECTED] Sent: 19 July 2004 00:48 To: [EMAIL PROTECTED] Subject: Re: Request Parameters in XSLT (Cocoon 2.1.5) Hi Ben, I'd suggest the following: Sitemap.xmap: <map:match pattern="output"> <map:generate src="input.xml" type="file"/> <map:transform src="output.xsl" type="xslt"> <map:parameter name="sort" value="{request-param:sort}" /> </map:transform> <map:serialize/> </map:match> and make sure in your output.xsl you have <xsl:param name="sort"/>, ie: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";> <xsl:param name="sort"/> <xsl:template match="/"> ... </xsl:template> </xsl:stylesheet> Hope that helps. Adam --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- This message has been scanned for viruses and dangerous content by MailScanner, and is believed to be clean. MailScanner thanks transtec Computers for their support. --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
