http://enroute.osgi.org/services/org.osgi.service.component.html


Sent from my iPhone

> On 18 Jul 2015, at 19:01, Alex Sviridov <[email protected]> wrote:
> 
> Thank you for your answer. Could you provide an example on my example - as 
> all is in development process and I can find old information.
> 
> I am sure that the example will be very short but we will understand what you 
> mean at 100%.
> 
> 
>> Суббота, 18 июля 2015, 17:02 +01:00 от Neil Bartlett <[email protected]>:
>> 
>> Hi Alex, you can use the @Reference annotation. 
>> 
>> Neil
>> 
>>> On Saturday, 18 July 2015 at 13:46, Alex Sviridov wrote:
>>> I use org.apache.felix.framework-4.6.1.jar and a bundle 
>>> org.apache.felix.scr-1.8.3-SNAPSHOT.jar
>>> 
>>> And I have two bundles - bundleA and bundleB. => totally I have three 
>>> bundles (A,B,scr)
>>> 
>>> And in every bundle I have one declarative service. For creating DS I use 
>>> annotations + maven bundle plugin.
>>> 
>>> How can I use connect one service to another other using DS annotations + 
>>> maven bundle plugin. I mean:
>>> 
>>> BundleA   
>>> #############################################################################################
>>> import org.osgi.service.component.annotations.Component;
>>> import org.osgi.service.component.annotations.ServiceScope;
>>> 
>>> @Component(
>>>     immediate = false,
>>>     property={"label=defaultA"},
>>>      scope=ServiceScope.PROTOTYPE
>>> )
>>> public class ClassA implements InterfaceA{
>>> ......
>>> }
>>> 
>>> BundleB   
>>> #############################################################################################
>>> import org.osgi.service.component.annotations.Component;
>>> import org.osgi.service.component.annotations.ServiceScope;
>>> 
>>> @Component(
>>>     immediate = false,
>>>     property={"label=defaultB"},
>>>      scope=ServiceScope.PROTOTYPE
>>> )
>>> public class ClassB implements InterfaceB{
>>> 
>>>    private InterfaceA aService; // HOW CAN I MAKE OSGI "INJECT" HERE 
>>> SERVICE A WITH LABEL=DEFAULTA???
>>>   .....
>>> }
>>> 
>>> 
>>> 
>>> -- 
>>> Alex Sviridov
> 
> 
> -- 
> Alex Sviridov

---------------------------------------------------------------------
To unsubscribe, e-mail: [email protected]
For additional commands, e-mail: [email protected]

Reply via email to