I've a spreadsheet with 2 3x2 matridces side by side (A1:D3). I want to mmult(A1:B3;transpose(C1:D3)); however, the result has the last row truncated. IOW, the resulting matrix is 2x3 instead of 3x3.
The spreadsheet also has the transpose stored separately in cells A5:C12, and then the mmult done with this separately stored transpose, and the result is a 3x3 matrix, as expected. Here's the printout of formulas in csv notation: 1,4,7,10 2,5,8,11 3,6,9,12 ,,, {=TRANSPOSE(C1:D3)},{=TRANSPOSE(C1:D3)},{=TRANSPOSE(C1:D3)}, {=TRANSPOSE(C1:D3)},{=TRANSPOSE(C1:D3)},{=TRANSPOSE(C1:D3)}, ,,, "{=MMULT(A1:B3,A5:C6)}","{=MMULT(A1:B3,A5:C6)}","{=MMULT(A1:B3,A5:C6)}", "{=MMULT(A1:B3,A5:C6)}","{=MMULT(A1:B3,A5:C6)}","{=MMULT(A1:B3,A5:C6)}", "{=MMULT(A1:B3,A5:C6)}","{=MMULT(A1:B3,A5:C6)}","{=MMULT(A1:B3,A5:C6)}", ,,, "{=MMULT(A1:B3,TRANSPOSE(C1:D3))}","{=MMULT(A1:B3,TRANSPOSE(C1:D3))}","{=MMULT(A1:B3,TRANSPOSE(C1:D3))}", "{=MMULT(A1:B3,TRANSPOSE(C1:D3))}","{=MMULT(A1:B3,TRANSPOSE(C1:D3))}","{=MMULT(A1:B3,TRANSPOSE(C1:D3))}", Why are there only 2 rows instead of 3 in the last result [the one done with mmult(a1:b3,transpose(c1:d3))]? TIA. -regards, Larry -- To unsubscribe e-mail to: users+unsubscr...@global.libreoffice.org Problems? http://www.libreoffice.org/get-help/mailing-lists/how-to-unsubscribe/ Posting guidelines + more: http://wiki.documentfoundation.org/Netiquette List archive: http://listarchives.libreoffice.org/global/users/ All messages sent to this list will be publicly archived and cannot be deleted