Hey and thanks for your fast answer. This is the data set:

  0.000001  0.000001  0.000001  0.000001  0.000001  0.000001  0.000001
0.000001  0.000001  0.000001  0.000001  0.000001  0.000001  0.000001
0.000002  0.000003  0.999997  0.999997  0.999997  0.999997  0.999998
1.000001  1.999997

Using the formula in the spreadsheet it gives the value: 0.328061419 (VAR)
and 0.5727664611 (STDEV)


And yes, i do mean CHISQ.INV :)

Thanks, Rui.

Cumprimentos,
Rui Pedro Caldeira

On Wed, Jul 8, 2015 at 7:24 PM, Brian Barker <b.m.bar...@btinternet.com>
wrote:

> At 18:44 08/07/2015 +0100, Rui Pedro Caldeira wrote:
>
>> I'm having some problems with the VAR and STDEV function, when executing
>> these lines of code. The average is well calculated but the remaining two
>> return very low, unrealistic and equal values (6.93018471335974E-310).
>>
>
> That value is 2^-1027 - which is probably the smallest floating-point
> value your system can represent without underflow.
>
> Have you compared the results produced from your data by equivalent normal
> formulae in a spreadsheet cell?
>
> Do you mean CHISQ.INV and not CHISQINV?
>
> Brian Barker
>
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