By default XmlSlurper is namespace aware so new XmlSlurper() is the same as
new XmlSlurper(false, true). I tried your example and I still get the
original prefixes. Maybe the difference is in how your code is removing
the node?
import groovy.xml.*
String xml = '''
<a:root xmlns:a="urn:a" xmlns:b="urn:b" xmlns:c="urn:c">
<a:child1>child1</a:child1>
<b:child2>
<b:content>
<b:dataNode>data</b:dataNode>
</b:content>
</b:child2>
<c:child3>child3</c:child3>
</a:root>
'''
def root = new XmlSlurper(false, true).parseText(xml)
String userInput = 'child2.content.dataNode'
def nodeToRemove = root
userInput.split("\\.").each {
nodeToRemove = nodeToRemove."${it}"
}
nodeToRemove.replaceNode {}
String newXml = XmlUtil.serialize(root)
def newRoot = new XmlSlurper(false, true).parseText(newXml)
println XmlUtil.serialize(newRoot)
assert newRoot.lookupNamespace('a') == 'urn:a'
assert newRoot.child3.lookupNamespace('c') == 'urn:c'
OUTPUT:
<?xml version="1.0" encoding="UTF-8"?><a:root xmlns:a="urn:a">
<a:child1>child1</a:child1>
<b:child2 xmlns:b="urn:b">
<b:content/>
</b:child2>
<c:child3 xmlns:c="urn:c">child3</c:child3>
</a:root>
On Fri, Apr 15, 2016 at 11:41 AM, Kenton Garner <[email protected]>
wrote:
> I appreciate your response.
>
>
>
> The problem is that the node that is being removed will be defined by the
> user during a configuration stage.
>
> Because of the generic nature the node to remove will be defined via a
> GPath string.
>
>
>
> I do not want to require the user to specify the GPath string with the
> namespace prefixes.
>
>
>
> To expand on your example…
>
> String xml = '''
>
> <a:root xmlns:a="urn:a" xmlns:b="urn:b" xmlns:c="urn:c">
>
> <a:child1>child1</a:child1>
>
> <b:child2>
>
> <b:content>
>
> <b:dataNode>
>
> Proprietary data to sanitize
>
> </b:dataNode>
>
> </b:content>
>
> </b:child2>
>
> <c:child3>child3</c:child3>
>
> </a:root>
>
> '''
>
> User would enter a GPath of “child2.content.dataNode” NOT
> “b:child2.b:content.b:dataNode”
>
>
>
> In order for this to work the XML has to be parsed with the XmlSlurper
> argument namespaceAware=true.
>
> def root = new XmlSlurper(false, true).parseText(xml)
>
>
>
> Now the println will show that the namespace prefixes are all altered a: =
> tag0: , b: = tag1: , c: = tag2: , etc.
>
> println XmlUtil.serialize(newRoot)
>
>
>
>
>
>
>
>
>
> *From:* John Wagenleitner [mailto:[email protected]]
> *Sent:* Friday, April 15, 2016 2:18 PM
> *To:* [email protected]
> *Subject:* Re: XmlSlurper Namespace Question
>
>
>
> Are you doing more than just removing nodes? The following seems to
> retain the namespace prefixes when serializing back out after removing a
> node.
>
>
>
>
>
> import groovy.xml.*
>
>
>
> String xml = '''
>
> <a:root xmlns:a="urn:a" xmlns:b="urn:b" xmlns:c="urn:c">
>
> <a:child1>child1</a:child1>
>
> <b:child2>child2</b:child2>
>
> <c:child3>child3</c:child3>
>
> </a:root>
>
> '''
>
>
>
> def root = new XmlSlurper().parseText(xml)
>
> root.child2.replaceNode {}
>
>
>
> String newXml = XmlUtil.serialize(root)
>
> def newRoot = new XmlSlurper().parseText(newXml)
>
>
>
> println XmlUtil.serialize(newRoot)
>
> assert newRoot.lookupNamespace('a') == 'urn:a'
>
> assert newRoot.child3.lookupNamespace('c') == 'urn:c'
>
>
>
>
>
> Don't believe there's a defined way to get all the namespaces from the
> original files, other than possibly picking at the
> non-public namespaceTagHints field or by visiting each node and using
> #namespaceURI() to get it's namespace.
>
>
>
> On Mon, Apr 11, 2016 at 9:40 AM, garneke <[email protected]> wrote:
>
> I have a requirement in my application to receive xml files from a user and
> filter out specific nodes based on a configuration option ( accepts GPath
> String ).
>
> This is fine.
> I can use XmlSlurper to parse the file and with the defined GPath I can
> find
> and remove the node and rewrite the file.
>
> My application is generic and can accept any XML.
> My user base is not terribly savvy so I need to be able to have the GPath
> specified without the namespace prefixes. This is also fine if the
> XmlSlurper is created to be namespace aware.
>
> *The problem is...*
> If my XmlSlurper is namespace aware and I remove a node, when I re-write
> the
> XML file all of the namespace prefixes get altered to "tag0:", "tag1:",
> "tag2:" etc.
>
> Is there a way to produce the XML with its original namespace prefixes?
> Is there someway I can query the original file for its namespaces and use
> that declare the namespaces for the slurper?
>
> Thanks in advance for your help.
>
>
>
>
>
>
> --
> View this message in context:
> http://groovy.329449.n5.nabble.com/XmlSlurper-Namespace-Question-tp5732293.html
> Sent from the Groovy Users mailing list archive at Nabble.com.
>
>
>
