Ahh!! I only saw this removeAll: public boolean *removeAll*(Object[] <http://docs.oracle.com/javase/7/docs/api/java/lang/Object[].html> items)
!! Thanks!!! On Thu, Jun 2, 2016 at 2:27 PM, Winnebeck, Jason < [email protected]> wrote: > If you want to actually edit the original map: > > > > def uidMap = [ > > a: 123, > > b: 456, > > c: 789 > > ] > > > > uidMap.entrySet().removeAll { it.key.startsWith('a') } > > > > If you want a new map, emmanuel’s solution using findAll is best. > > > > Jason > > > > *From:* Guy Matz [mailto:[email protected]] > *Sent:* Thursday, June 02, 2016 2:18 PM > *To:* [email protected] > *Subject:* Looping through a hashmap & removing elements > > > > Hi! I want to loop through a hashmap and delete some elements based on > some criteria . . . I thought there would be some slick groovy method - in > the spirit of findAll, etc. - to do this, but couldn't find it . . . my > java developer workmate suggested: > > > > iter = uidMap.entrySet().iterator() > *while *(iter.hasNext()) { > entry = iter.next() > key = entry.key > value = entry.value > > if (bla, blah, blah) { > > iter.remove() > > } > > > > Is there a groovier way? > > > > Thanks! > > Guy > > ------------------------------ > This email message and any attachments are for the sole use of the > intended recipient(s). Any unauthorized review, use, disclosure or > distribution is prohibited. If you are not the intended recipient, please > contact the sender by reply email and destroy all copies of the original > message and any attachments. >
