I think I have confused a bit, I'm not replicating anything.
We have a multi user scenario where every user gets a home folder. Users
can share contents from his/her home with other users. For every
file/folder to be shared we are mixing referenceable and creating a
linkedFile as below:
Node shareable = //get the node to share
shareable.addMixin("mix:referenceable").
Then create a link in another users home
Node linkedNode =
sharedfolder.addNode(shareable.getName,JcrConstants.NT_LINKEDFILE)
linkedNode.setProperty("jcr:content", contentNode)
I don't know how to dereference and descent a linked folder for a query:
"select f.* from [nt:base] as f where ISDESCENDANTNODE(f,'/folder')".
I'm having a look at your github project.
Rahul.
On Sun, Apr 3, 2016 at 1:56 AM, Clay Ferguson <[email protected]> wrote:
> If you want to create a replica of your data, chances are (no offence)
> that you are misunderstanding something. If you can please share why you
> think the duplicate data is necessary.
>
> But if you really want to duplicate using links to the actual nodes, one
> way is to just use a property on the "shadow tree" that points to the real
> node via jcr:uuid value as a property. So the property is on the node that
> 'points to' the other node. Read up also on "mix:referenceable" before you
> get started.
>
> check out my meta64.com codebase. That app is all about JCR/tree editing,
> and has some searching examples also using isdescendantnode a lot.
>
> Best regards,
> Clay Ferguson
> [email protected]
>
>
> On Sat, Apr 2, 2016 at 10:41 AM, Rahul Raj <
> [email protected]>
> wrote:
>
> > I can add a node property to the leaf nodes. Will it help in
> dereferencing
> > the linked files?
> >
> > Let me make the question clear with the structure below.
> >
> > rootfolder
> > -nt:file(file1)
> > -nt:folder(folder1)
> > -nt:file(file2)
> > -nt:file(file3)
> > -nt:file(file4)
> >
> > Here, a query like select f.* from [nt:file] as f where
> > ISDESCENDANTNODE(f,'/rootfolder')
> > fetches all files from root folder.
> >
> > Now the same files are linked to form a sharedfolder as below:
> >
> > sharedfolder
> > -nt:linkedfile(to file1)
> > -nt:linkedfile(to folder1)
> > -file2
> > -file3
> > -nt:linkedfile(to file4)
> >
> > What query would achieve similar results?
> >
> > Rahul
> >
> > On Sat, Apr 2, 2016 at 8:29 PM, Clay Ferguson <[email protected]> wrote:
> >
> > > probably the way that makes most sense is make your files (leaf nodes)
> a
> > > specific node type, or else let them all have a property that you can
> > test
> > > for like "objType=file" or something. Even if you found a solution
> based
> > on
> > > finding nodes that are leaf nodes, or have no children or whatever, i
> > would
> > > still go with the approach I just said, because it's clean, and allows
> > more
> > > nodes to be attached to the tree later on without "breaking your logic"
> > > about how to find all files under some branch.
> > >
> > > Best regards,
> > > Clay Ferguson
> > > [email protected]
> > >
> > >
> > > On Fri, Apr 1, 2016 at 11:30 PM, Rahul Raj <
> > > [email protected]>
> > > wrote:
> > >
> > > > We have a shared directory structure as shown below. The shared
> folder
> > > has
> > > > links to files and folders.
> > > >
> > > > sharedfolder
> > > > -nt:linkedfile(file1)
> > > > -nt:linkedfile(folder1)
> > > > -file2
> > > > -file3
> > > > -nt:linkedfile(file4)
> > > >
> > > > How to write a jcr sql2 query that will fetch all of
> file1,file2,file3
> > > and
> > > > file4 while performing a ISDESCENDANTNODE on the sharedfolder
> > > > I could not figure out a way to de-reference the linkedFiles while
> > using
> > > > ISDESCENDANTNODE.
> > > >
> > > >
> > > > Regards,
> > > > Rahul
> > > >
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